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In the mathematical theory of elasticity the strain Barré de Saint-Venant derived the compatibility condition for an arbitrary symmetric second rank tensor field to be of this form, this has now been generalized to higher rank symmetric tensor fields. [edit] Rank 2 tensor fieldsThe integrability condition takes the form of the vanishing of the Saint-Venant's tensor The result that, on a simply connected domain W=0 implies that strain is the symmetric derivative of some vector field, was first described by Barré de Saint-Venant in 1864 and proved rigorously by Beltrami in 1886[2]. For non-simply connected domains there are finite dimensional spaces of symmetric tensors with vanishing Saint-Venant's tensor that are not the symmetric derivative of a vector field. The situation is analogous to de Rham cohomology[3] Due to the symmetry conditions Wijkl = Wklij = − Wjikl = Wijlk there are only six (in the three dimensional case) distinct components of W For example all components can be deduced from Wijkl the indices ijkl=2323, 2331, 1223, 1313, 1312 and 1212. The six components in such minimal sets are not independent as functions as they satisfy partial differential equations such as and there are two further relations obtained by cyclic permutation. In its simplest form of course the components of The relation between Saint-Venant's compatibility condition and Poincare's lemma can be understood more clearly using the operator where
where indices following a semicolon indicate covariant differentiation. The vanishing of W(T) is thus the integrability condition for local existence of U in the Euclidean case. [edit] Generalization to higher rank tensorsSaint-Vanants compatibility condition can be thought of as an analogue, for symmetric tensor fields, of Poincare's lemma for skew-symmetric tensor fields (differential forms). The result can be generalized to higher rank symmetric tensor fields.[4] Let F be a symmetric rank-k tensor field on an open set in n-dimensional Euclidean space, then the symmetric derivative is the rank k+1 tensor field defined by where we use the classical notation that indices following a comma indicate differentiation and groups of indices enclosed in brackets indicate symmetrization over those indices. The Saint-Venant tensor W of a symmetric rank-k tensor field T is defined by with On a simply connected domain in Euclidean space W = 0 implies that T = dF for some rank k-1 symmetric tensor field F. [edit] References
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